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Question

A block of mass 500g slides down a a rough incline plane of inclination 53o with a uniform speed. Find the work done against the friction as the block slides through 2m [g=10m/s2]

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Solution

Since it is moving with constant speed work done =Kt=0
Wgravity=Wfriction
Wfriction=Wgravity
=Mg(H2H1)
sin53=H2H12
H2H1=85
45=H2H12
=5001000×10×85
=8 joules
978055_1069407_ans_59e7bb2576ec47fb869db06f9c1403bb.png

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