Question

A block of mass $5kg$ is on a rough horizontal surface and is at rest. Now a force of $24N$ is imparted to it with negligible impulse. If the coefficient of kinetic friction is $0.4$ and $g=9.8m/s^2$, then the acceleration of the block is

Answer 1

$m=5kg$

$F=24N$

$\mu =0.4$

$g=9.8m/s^2$

$Friction,f=\mu mg=0.4\times 5\times 9.8=19.6N$

$Netforce=F-f=24-19.6=4.4N$

$Acceleration,a=\frac{4.4}{5}=0.88m/s^2$