Question

A block of mass $5kg$ slides down an inclined plane which makes an angle $\theta ={60}^o$ with the horizontal. The coefficient of fricion between the block and the plane is $\mu =3/4$. The force exerted by the block on the plane is ($g=10m/s^2$)

• A. $25N$
• B. $125/4N$
• C. $15N$
• D. $75/4N$

Answer 1

The correct option is A $25N$

N=force exerted by block on the plane

=$5\times 10\times \frac{1}{2}$

=25N