A block of mass 70kg is kept on a rough horizontal surface (μ=0.4). A person is trying to pull the block by applying a horizontal force, but the block is not moving. The net contact force exerted by the surface on the block is F, then;
A
F=280N
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B
F=754N
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C
700N≤F≤754N
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D
F=700N
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Solution
The correct option is C700N≤F≤754N Draw a free body diagram of the block.
Given, mass of block, m = 70 kg,
To find, frictional force, f
Formula used : F=√N2+f2
Normal force,N=70kg×10N/m2=700N
Frictional force,f=μN=0.4×700N=280N
Net contact force: F=√N2+f2 N≤F≤√N2+f2 700N≤F≤√(700N)2+(280N)2 ⇒700N≤F≤754N