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Static Friction

A block of ma...

Question

A block of mass 9 kg, lying on a friction-less table, is connected to a block of mass 1 kg by means of a string which passes over a friction-less pulley as shown. The tension in the string is $(g = 10 m / s^{2})$

A

1N

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B

4N

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C

7N

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D

9N

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Solution

The correct option is D 9N
Net downward force on 1 kg : $1 g - T = 1 a$
So, $10 - T = a$ (1)
For second block of 9kg : $T = 9 a$ ___(2)
equating both equations $a = 1 m / s^{2}$
And $T = 9 N$

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