A block of mass $m_{1}$ is pulled along a horizontal frictionless surface by a rope of mass $m_{2}$ . If a force F is applied at the free end of the rope, the force exerted by the rope on the block is

\frac{m_{2}}{m_{1} + m_{2}} F

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{m_{2}}{m_{1} - m_{2}} F

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{m_{1}}{m_{1} + m_{2}} F

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{m_{1}}{m_{1} - m_{2}} F

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{m_{1}}{m_{1} + m_{2}} F$
Acceleration on the system,
$a = \frac{F}{m_{1} + m_{2}}$
Force exerted by the rope on block, $F_{1} = m_{1} a$
$= \frac{m_{1} F}{m_{1} + m_{2}}$

Suggest Corrections

Similar questions

Q. A block of mass

M

is pulled along a horizontal frictionless surface by a rope of mass

m

. If a force

P

is applied at the free end of the rope, the force exerted by the rope on the block is :

A block of mass M is pulled along a horizontal frictionless suface by a rope of mass m. If a force F is applied at the free end of the rope, the net force exerted on the block will be

Q. A block of mass

M

is pulled along a horizontal surface by a rope of mass

m

by applying a force

F

at one end of the rope. The force which the rope exerts on the block is :

Q. A block of mass

M

is pulled along a horizontal frictionless surface by a rope of mass

m

. If a force

F

is applied at one end of the rope, the force which the rope exerts on the block is:

Q. A block of mass

M

is pulled along horizontal frictionless surface by a rope of mass

m

. Force

P

is applied at one end of rope. The force which the rope exerts on the block is

Join BYJU'S Learning Program

A block of mass m1 is pulled along a horizontal frictionless surface by a rope of mass m2. If a force F is applied at the free end of the rope, the force exerted by the rope on the block is

The correct option is C m1m1+m2FAcceleration on the system, a=Fm1+m2 Force exerted by the rope on block, F1=m1a =m1Fm1+m2

A block of mass $m_{1}$ is pulled along a horizontal frictionless surface by a rope of mass $m_{2}$ . If a force F is applied at the free end of the rope, the force exerted by the rope on the block is

The correct option is C $\frac{m_{1}}{m_{1} + m_{2}} F$
Acceleration on the system,
$a = \frac{F}{m_{1} + m_{2}}$
Force exerted by the rope on block, $F_{1} = m_{1} a$
$= \frac{m_{1} F}{m_{1} + m_{2}}$