wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A block of mass m1 kg is horizontally thrown with a velocity of 10m/s on a stationary long plank of mass 2kg whose surface has a μ=0.5. The plank rests on frictionless surface. Find the time when m1 comes to rest w.r.t. plank.

A
4/3 sec
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
3/4 sec
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
8/3 sec
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3/8 sec
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 4/3 sec
There will be friction force between mass and plank until both mass and plank has same velocity.
Let the block be going in forward direction initially, so the frictional force on it will be in backward direction and on plank will be in forward direction.
Normal force between block & plank is 1×g=10N
Frictional Force will be μN=0.5×10=5N
Deceleration of block will be 51=5 and acceleration of plank will be 52=2.5
Final speed of both plank & block are equal, so
v=u+atv=0+2.5t=105t10=7.5tt=43s

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon