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Question

A block of mass (m=1 kg) is released from rest over a circular curved path, as shown in diagram. The work done (in joules) by normal force, when block is displaced by θ=45 is

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Solution

Normal force is always perpendicular to surface of contact and displacement is along surface of contact.
So, the angle between normal force and displacement is 90
Work done by normal force is W=Nd cos θ
W=Nd cos 90=0

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