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Question

A block of mass m2 is placed on a horizontal table and another block of mass m1 is placed on top of it. An increasing horizontal force F=αt is exerted on the upper block but the lower block never moves as a result. If the co-efficient of friction between the blocks is μ1 and the between the lower block and the table is μ2, then what is the maximum possible value of μ1/μ2?

A
m2m1
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B
1+m2m1
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C
m1m2
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D
1+m1m2
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Solution

The correct option is A 1+m2m1
f2= acting friction between lower block & the table.
f1= acting friction between lower block & upper block.
m2 never moves.
So f1f21
So friction acting in between the block is always less than or equal to friction acting between lower block & table.
So μ1m1gμ2(m1+m2)g
μ1μ2m1+m2m1
mu1μ21+m2m1
So maximum value of μ1μ2=1+m2m1.
812063_876183_ans_a0f5378903ee4d87945504495b1ea93d.jpg

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