Question

A block of mass $m=2kg$ is pulled by a focus $f=40N$ upward through a height $h=2$ meter. Find the work done on the block by the applied force $F$ and its weight $mg$. ($g=10m/{sec}^2$)

• A. $40J,-40J$
• B. $80J,-40J$
• C. $40J,80J$
• D. $80J,-80J44$

Answer 1

The correct option is C $40J,80J$

$80J,-40J$

$W=mgh=2\times 10\times 2=-40J$

$W=Fd\cos \theta =40\times 2\times \cos 0=80J$