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Question

A block of mass m=3 kg is pulled by a force F=50 N upwards through 2 m height in vertical direction. It takes 8 seconds to lift the mass. Find the average power delivered by the force.

A
12.5 W
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B
25 W
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C
20 W
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D
50 W
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Solution

The correct option is A 12.5 W
Work done by the applied force WF=Fhcosθ, where h is height.
Here, θ=0, because displacement is in the same direction of force applied.
WF=Fhcos0=Fh=50×2
WF=100 J

Average Power =Total work done by the forceTotal time taken
=1008=12.5 W

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