A block of mass m=3kg is pulled by a force F=50N upwards through 2m height in vertical direction. It takes 8seconds to lift the mass. Find the average power delivered by the force.
A
12.5W
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B
25W
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C
20W
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D
50W
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Solution
The correct option is A12.5W Work done by the applied force WF=Fhcosθ, where h is height.
Here, θ=0∘, because displacement is in the same direction of force applied. ⇒WF=Fhcos0∘=Fh=50×2 ⇒WF=100J
Average Power =Total work done by the forceTotal time taken =1008=12.5W