A block of mass m=5kg is resting on a rough horizontal surface for which the coefficient of friction is 0.2 when force F=40N is applied. The acceleration of the block will be (g=10m/s)
A
3m/s2
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B
2m/s2
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C
6m/s2
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D
83m/s2
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Solution
The correct option is C6m/s2 Mass of block =5kg F=40N μ=0.2 g=10m/s² friction, f = μmg = 0.2×5×10 = 10N net force =F−f=40−10=30N acceleration 30/5=6m/s2