CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
59
You visited us 59 times! Enjoying our articles? Unlock Full Access!
Question

A block of mass m=5kg is resting on a rough horizontal surface for which the coefficient of friction is 0.2 when force F=40N is applied. The acceleration of the block will be (g=10m/s)

A
3m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
6m/s2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
83m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 6m/s2
Mass of block =5kg
F=40N
μ=0.2
g=10m/s²
friction, f = μmg = 0.2×5×10 = 10N
net force =Ff=4010=30N
acceleration 30/5=6m/s2
Hence,
option (C) is correct answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Acceleration
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon