A block of mass $m$ and a pan of equal mass are connected by a string that passes over two ideal pulleys as shown in the figure. Initially when the system is at rest ,a piece of putty of mass m fall on the pan and sticks to it . If the piece of putty strikes the pan with a speed $v_{0}$ . Select the correct statement (s).

Speed of the block immediately after the putty sticks to the pain is zero.

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Speed of the block immediately after the putty sticks to the pan is

v_{0} / 3

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Momentum of the block -pan and putty system remains conserved during the collision.

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Momentum of the block pan and putty system does not remain conserved during the collision.

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Solution

The correct option is B Speed of the block immediately after the putty sticks to the pan is $v_{0} / 3$ .
The velocity of the particle just before the collision is $V_{0}$

Since the momentum of the momentum of the system is remain same,

$m V_{0} = 3 m V \Rightarrow V = \frac{V_{0}}{3}$

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The correct option is B Speed of the block immediately after the putty sticks to the pan is v0/3.The velocity of the particle just before the collision is V0Since the momentum of the momentum of the system is remain same,mV0=3mV⇒V=V03

The correct option is B Speed of the block immediately after the putty sticks to the pan is $v_{0} / 3$ .
The velocity of the particle just before the collision is $V_{0}$

Since the momentum of the momentum of the system is remain same,

$m V_{0} = 3 m V \Rightarrow V = \frac{V_{0}}{3}$