A block of mass m at the end of a string is whirled round in a vertical circle of radius r. The critical speed of the block at the top of its swing below which the string would slacken before block reaches the top is
A
√2rg
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B
√3rg
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C
√rg
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D
√5rg
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Solution
The correct option is C√rg the string will not slack if the centrifugal force on the particle is greater then or equal to the weight of mass i.e. mv2r≥mg⇒v≥√rg⇒vc=√rg