A block of mass m initially at rest is dropped from a height h on to a spring of force constant k. the maximum compression in the spring is x then

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B

Change in gravitational potential energy
= Elastic potential energy stored in compressed spring
$\Rightarrow m g (h + x) = \frac{1}{2} k x^{2}$

Suggest Corrections

Similar questions

0.4 m

k = 1960 N / m

2

0.4

K

1960 N m^{- 1}

A 2kg block is dropped from a height of 0.4 m on a spring of force constant K = 1960 Nm−1. The maximum compression of the spring is

0.1 m

0.2 m

0.3 m

0.4 m

2 k g

5 m

K

2 \times 10^{6}

Join BYJU'S Learning Program