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Work Energy Theorem Application

A block of ma...

Question

A block of mass m is attached to one end of a massless spring which is suspended vertically from a fixed point. The mass is held in hand so that the spring is neither stretched nor compressed. Suddenly the support of the hand is removed. The lowest position attained by the mass during oscillation is $4 c m$ below the point, where it was held in hand. The amplitude of the oscillation is then

A

1 c m

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B

2 c m

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C

3 c m

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D

4 c m

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Solution

The correct option is C $2 c m$
The mass m will be oscillating about a position in between the lowest position and the position, where it was held in hand. Therefore, the lowest position and the position of hand will be extreme positions for the oscillations of mass m.
The half of this distance will be amplitude of oscillation. Hence, the amplitude of the oscillation is
$A = \frac{4 c m}{2} = 2 c m$

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