A block of mass ′m′ is attached with a massless spring of force constant k. The block is placed over a rough incline surface for which the coefficient of friction is μ=34. The minimum value of M required to moved the block up the plane is (Neglect mass of pulley, string and friction in pulley).
Given,
Coefficient of friction, μ=34
Mass of block A is M
Mass of block B is m
When block A moves to a distance x, then spring will stretch to x value. And it will lift the block B
For, block B and spring
Maximum Force required on spring = gravity force component + friction force
Force in the spring, F=kx=mgsin37o+μmgcos37o
⇒kx=mg35+34mg45=6mg5……(1)
For, block A and spring
Kinetic energy = Potential energy
12kx2=Mgx
kx=2Mg...... (2)
From (1) and (2)
6mg5=2Mg
M=3m5
Required mass of A is 3m5 , to lift mass B