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Question

A block of mass m is attached with a spring of force constant k. The block is kept on a frictionless plank. The other end of the spring is connected with the plank. Mass of the plank is M and it is also kept on a frictionless surface.

Initially, the system is stationary. A sharp impulse P is applied on the block as shown. The maximum compression in the spring will be


A

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B

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C

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D

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Solution

The correct option is A


Initial velocity of M:v1=pm

At the time of maximum compression, velocity of both is same.

Using, conservation of momentum

(M + m) v = p v=PM+m

Apply conservation of energy:

12mv12=12(M+m)v2+12kxm2

Solve to get xm=PMk(M+m)m


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