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Question

A block of mass M is attached with the springs as shown .If the block is slightly displaced the time period of SHM for the block shown in the figure will be
1228998_c0ead2b0b9024d10baabbc974314c95d.png

A
2πm9k
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B
2πmk
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C
4π3m9k
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D
πm2k
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Solution

The correct option is A 2πm9k
When system moves x units in right then Pulley 1 and Pulley 2 moves xunits in right and required string for each pulley is 2x.
Therefore , both spring are elongated by 2x.
Force exerted=k(2x)
Tension in String(T)=k(2x)
Force exerted by right spring due to x displacement =kx
Net force =2T+2T+kx=9kx
Now net force =mω2x=9kx
Or , ω=9km
Now time period for SHM=T=2πω=2πm9k.


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