A block of mass M is hanging over a smooth and light pulley through a light string. The other end of the string is pulled by a constant force F. The kinetic energy of the block increases by 20 J in 1s.
A
The tension in the string is Mg.
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B
The tension in the string is F.
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C
The work done by the tension on the block is 20 J in the above 1 s.
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D
The work done by the force of gravity is - 20 J in the above 1 s.
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Solution
The correct option is B The tension in the string is F.
As tension is same throughout a mass less string tension = F As per work enough theorem work done by all focus (F and weight) =ΔKE=20J