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Question

A block of mass M is hanging over a smooth and light pulley through a light string. The other end of the string is pulled by a constant force F. If kinetic energy of the block increases by 20J in 1s. Then:

A
Tension in the string is Mg.
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B
Tension in the string is F.
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C
Work done by the tension on the block is 20J in 1sec.
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D
Work done by the force of gravity is 20J in 1sec.
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Solution

The correct option is B Tension in the string is F.
Tension in the string would be equal to the force exerted on the other end of the string. Thus T=F.
Net work done on the body is equal to the gain in kinetic energy of the block.
Thus increase in kinetic energy in 1s=Work done by tension on the block in 1s+Work done by gravity on the block in 1s.
20J=WT+WG
Thus WT20J
WG20J

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