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Question

A block of mass m is kept on a platform which starts from rest with constant acceleration g2 upwards as shown in the figure. Work done by the normal reaction on the block in time t is:

A
mg2t28
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B
3mg2t28
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C
\N
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D
mg2t28
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Solution

The correct option is B 3mg2t28

From FBD,
Normal reaction force on the block is:
N=m(g+a)=m(g+g2)=3mg2

Displacement of the block
S=0+12at2=12(g2)t2(u=0)
Here, a=g2(given)
Work done = Force × Displacement
(Force is constant)
W=3mg2×gt24=3mg2t28

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