Question

A block of mass m is kept on the edge of a horizontal turn table of radius R, which is rotating with constant angular velocity $\omega$ (along with the block) about its axis. If coefficient of friction force between block and table.

Answer 1

The block. in Fig. does not accelerate vertically. Therefore, we model it as a particle in equilibrium in the vertical direction. It experiences a centripetal acceleration in the horizontal direction. In this case, centripetal force is provided by friction.
$\sum F_y=N-mg=0$
N = mg (i)
$\sum F_x=f=m{a}_c=m{\omega }^{2}R$ (ii)
Friction force = centripetal force = $m{\omega }^{2}R$