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Question

A block of mass m is moving with a constant acceleration a on a rough horizontal plane. If the coefficient of friction between the block and ground is μ, the power delivered by the external agent after a time t from the beginning of motion is

A
ma2t
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B
μmgat
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C
μm(a+μg)gt
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D
m(a+μg)at
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Solution

The correct option is D m(a+μg)at
Let F be the force applied by the external agent.

Let v be the speed of the block at the time t

Instantaneous power delivered, P=F.V

Applying Newton's second law,

Ff=ma

F=f+ma

P=(f+ma)v

f=μmg

Also, v=at (u=0)

P=(μmg+ma)v=m(a+μg).at

Hence, option (d) is the correct answer.







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