A block of mass m is placed on a smooth wedge of inclination θ. The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block (g is the acceleration due to gravity) will be
A
mgcosθ
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B
mgsinθ
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C
mg
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D
mgcosθ
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Solution
The correct option is Dmgcosθ
Applying pseudo force on block
As block does not slip, macosθ=mgsinθ a=gtanθ……(1) N=masinθ+mgcosθ N=mgtanθsinθ+mgcosθ N=mgcosθ