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Question

A block of mass m is placed on a wedge. The wedge can be accelerated in four manners marked as (1), (2), (3) and (4) as shown. If the normal reactions in situation (1), (2), (3) and (4) are N1,N2,N3 and N4 respectively and acceleration with which the block slides on the wedge in situations are b1,b2,b3 and b4 respectively then:

A
N3>N1>N2>N4
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B
N4>N3>N1>N2
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C
b2>b3>b4>b1
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D
b2>b3>b1>b4
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Solution

The correct option is C b2>b3>b4>b1
(1)
Balancing forces perpendicular to incline N1=mgcos37 +masin37
N1=45mg+35ma
and along incline
mgsin37macos37=mb1
b1=35g45a
(2)

Similarly for this case get N2=45mg35ma
and b2=35g+45a

(3)
Similarly N3=45mg+45ma
and b3=35g+35a
(4)

Similarly N4=45mg45ma
b4=35g35a

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