A block of mass 'M' is placed on the top of a bigger inclined plane of mass '10M' as shown in figure. All the surfaces are frictionless. The system is released from rest. Find the distance moved by the bigger block at the instant the smaller block reaches the ground.

0.2m

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0.4m

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0.1m

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0.3m

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Solution

The correct option is A
0.2m

If the bigger block moves right by a distance x, the smaller block move towrards left by (2.2 - x)
We know ,
$δ$ $X_{c o m}$ = $\frac{m_{1} △ X_{1} + m_{2} △ X_{2}}{m_{1} + m_{2}}$
As there is no net external force in horizontal direction,
$δ$ $X_{c o m}$ = 0
$\Rightarrow$ $\frac{m_{1} △ X_{1} + m_{2} △ X_{2}}{m_{1} + m_{2}}$ = 0
10MX - M(2.2 - x)
10X = 2.2 - x
11x = 2.2
X = 0.2 m

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