A block of mass M is pulled along a horizontal frictionless surface by a rope of mass m. If a force F is applied at one end of the rope, the force which the rope exerts on the block is:
A
F/(M+m)
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B
F
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C
FM/(m+M)
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D
0
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Solution
The correct option is C FM/(m+M)
Acceleration of block and rope assembly in horizontal direction will be equal to F/M(m+M). Free body diagram of block M is Equation of motion in horizontal direction is T = Ma Subsituting value of a, T=MF/M(m+M) Hence rope will apply FM/M(m+M) force on block of mass M.