A block of mass M is pulled along a horizontal rough surface by a rope of mass m by applying a force F at one end of the rope. f is the friction between block and the surface. The force which the rope exerts on the block is:
A
FMm+M+f
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B
mFm+M−f
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C
mf+FMM+m
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D
MF−fmM−m
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Solution
The correct option is Bmf+FMM+m Friction force is only applied on M, it is f. (M+m)a=F−f⇒a=F−fM+m So, the force due to rope is: Ma+f=mf+FMM+m