You visited us 8 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Constrained Motion : Intuitive Approach

A block of ma...

Question

A block of mass $m$ is pulled by a string acts with passes over a smooth pulley $P$ fitted with the wedge of mass $M$ . A horizontal force $F = m g$ acts on the string. If the string is massless and frictionless, assuming frictionless contacting surfaces and $θ = cos - 1 4 / 5$ , then :

N = 4 / 5 m g

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

N =

Normal reaction on block

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a_{1} = 17 g / 25

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a_{1} =

acceleration of

^{'} m^{'}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $N = 4 / 5 m g$
Given $cos θ = \frac{4}{5}$
$m a = F - m g sin θ$
$m a = m g (1 - \frac{3}{5})$
$a = g (\frac{2}{5})$
and $N = m g cos θ = m g (\frac{4}{5})$
Hence, the option $A$ is the correct answer.

Suggest Corrections

Similar questions

Q. A block of mass

M

placed on a frictionless horizontal table is pulled by another block of mass

m

hanging vertically by a massless string passing over a frictionless pulley. The tension in the string is :

Q. Two blocks of masses

m

and

2 m

are placed on triangular wedge by means of a massless inextensible string over a frictionless fixed pulley. Surface of contact between the masses and wedge is frictionless and wedge makes

45^{\circ}

with horizontal on both sides as shown in figure. The tensions in the string

(T)

Q. Two blocks of masses

m

and

2 m

are placed on triangular wedge by means of a massless inextensible string over a frictionless fixed pulley. Surface of contact between the masses and wedge is frictionless and wedge makes

45^{\circ}

with horizontal on both sides as shown in figure. The tensions in the string

(T)

Q. Two smooth blocks of masses m and m' connected by a light inextensible string are moving on a smooth wedge of mass M. If a force F acts on the blocks. Find the (a) acceleration of the wedge and (b) value of F.

Two blocks of mass m and 2m are connected as shown in figure. A force F is acting on the block of mass 4m. Pulley is massless and string is light and inextensible. All the surfaces are smooth.

Contact force between ground and the 4m mass under the previous problem condition is

Join BYJU'S Learning Program

A block of mass m is pulled by a string acts with passes over a smooth pulley P fitted with the wedge of mass M. A horizontal force F=mg acts on the string. If the string is massless and frictionless, assuming frictionless contacting surfaces and θ=cos−1 4/5, then :

The correct option is A N=4/5 mgGiven cosθ=45ma=F−mgsinθma=mg(1−35)a=g(25)and N=mgcosθ=mg(45)Hence, the option A is the correct answer.

A block of mass $m$ is pulled by a string acts with passes over a smooth pulley $P$ fitted with the wedge of mass $M$ . A horizontal force $F = m g$ acts on the string. If the string is massless and frictionless, assuming frictionless contacting surfaces and $θ = cos - 1 4 / 5$ , then :

The correct option is A $N = 4 / 5 m g$
Given $cos θ = \frac{4}{5}$
$m a = F - m g sin θ$
$m a = m g (1 - \frac{3}{5})$
$a = g (\frac{2}{5})$
and $N = m g cos θ = m g (\frac{4}{5})$
Hence, the option $A$ is the correct answer.