A block of mass m is pulled horizontally on a smooth surface by a force of $2 N$ through a distance of $5 m$ . Find the work done in the process.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C

$W = F \times s \times c o s θ$

$F = 2 N$

$s = 5 m$

$θ = 0^{\circ}$

$c o s θ = 1$

$W = 2 \times 5 \times 1 = 10 J o u l e s$

Suggest Corrections

Similar questions

A force of $10 N$ acts on a block at an angle of $60^{\circ}$ and because of which it moves by $10 m$ on a frictionless surface. Find the work done by the force on the block.

A body of mass 10 kg is dropped to the ground from a height of 10 metres. The work done by the gravitational force is $g = 9.8 m / s e c^{2}$

The displacement of a particle of mass 1 kg on a horizontal smooth surface is a function of time given by

$x = \frac{1}{3} t^{3}$ . Find out the work done by the external agent for the first one second.

What is the work done in moving a charge of 0.4 C across two points having a potential difference of 8 V?

A force $F = (5^i + 3^j)$ newton is applied over a particle which displaces it from its origin to the point $r = (2^i - 1^j)$ metre. The work done on the particle is

Join BYJU'S Learning Program

A block of mass m is pulled horizontally on a smooth surface by a force of 2 N through a distance of 5 m. Find the work done in the process.

The correct option is C W=F×s×cosθ F=2N s=5m θ=0∘ cosθ=1 W=2×5×1=10 Joules

A block of mass m is pulled horizontally on a smooth surface by a force of $2 N$ through a distance of $5 m$ . Find the work done in the process.

The correct option is C

$W = F \times s \times c o s θ$

$F = 2 N$

$s = 5 m$

$θ = 0^{\circ}$

$c o s θ = 1$

$W = 2 \times 5 \times 1 = 10 J o u l e s$