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Question

A block of mass 'm' is pushed against a spring of spring constant K fixed at other end to a wall. The block can slide of a frictionless table as shown. The nature length of the origin is Lo. It is compressed to half its natural length and leased. Find the velocity of the block as a function of its distance from the wall.

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Solution

Given,

Initial natural length,= Lo

There initial compression = L0/2
Energy stored in the spring, = 12K(Lo2 )2=18KL20
This it moves small distance X, say the velocity it has is v and so
12K[L02X]2+12mv2=18KL20
12KX212K(LoX)+12mv2=0
KX2KLoX+mv2=0
v2=[LoXX2]Km
v= K(LoXX2) m

Hence, velocity and distance relation is  K(LoXX2) m


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