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Pseudo Force

A block of ma...

Question

A block of mass m is pushed towards a movable wedge to mass $β$ m and height h with a velocity u. All surfaces are smooth. When the block collides with the wedge, the velocity of centre of mass of block wedge system will be -

u

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\frac{u}{1 + β}

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u (1 + β)

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Solution

The correct option is B $\frac{u}{1 + β}$
$T h e r e i s n o e x t e r n a l f o r c e a c t i n g o n t h e s y s t e m s o v e l o c i t y o f C O M w o n t c h a n g e .$
$i n i t i a l V_{C o m} = \frac{m u}{m (1 + β)} = \frac{u}{(1 + β)} = f i n a l V_{C o m}$

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A block of mass m is pushed towards a movable wedge to mass βm and height h with a velocity u. All surfaces are smooth. When the block collides with the wedge, the velocity of centre of mass of block wedge system will be -

The correct option is B u1+βThereisnoexternalforceactingonthesystemsovelocityofCOMwontchange.initialVCom=mum(1+β)=u(1+β)=finalVCom

A block of mass m is pushed towards a movable wedge to mass $β$ m and height h with a velocity u. All surfaces are smooth. When the block collides with the wedge, the velocity of centre of mass of block wedge system will be -

The correct option is B $\frac{u}{1 + β}$
$T h e r e i s n o e x t e r n a l f o r c e a c t i n g o n t h e s y s t e m s o v e l o c i t y o f C O M w o n t c h a n g e .$
$i n i t i a l V_{C o m} = \frac{m u}{m (1 + β)} = \frac{u}{(1 + β)} = f i n a l V_{C o m}$