A block of mass $m$ is resting on a horizontal surface. The coefficient of friction is 0.4. A horizontal force of $10 N$ is needed to move the block. Normal reaction $N$ acting is

$50 N$

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$125 N$

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$25 N$

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$5 N$

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Solution

The correct option is C
$25 N$

Given

Force needed = $10 N$

Force needed is the amount to overcome friction

Frictional force = Coefficient of friction $\times$ Normal reaction

$\Rightarrow 10$ = $0.4 \times N$

$∴ N$ = $25 N$

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A block of mass m is resting on a horizontal surface. The coefficient of friction is 0.4. A horizontal force of 10N is needed to move the block. Normal reaction N acting is

The correct option is C 25 N Given Force needed = 10N Force needed is the amount to overcome friction Frictional force = Coefficient of friction× Normal reaction ⇒10 = 0.4×N ∴N = 25 N

A block of mass $m$ is resting on a horizontal surface. The coefficient of friction is 0.4. A horizontal force of $10 N$ is needed to move the block. Normal reaction $N$ acting is

The correct option is C
$25 N$

Given

Force needed = $10 N$

Force needed is the amount to overcome friction

Frictional force = Coefficient of friction $\times$ Normal reaction

$\Rightarrow 10$ = $0.4 \times N$

$∴ N$ = $25 N$