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Question

A block of mass m is resting on a wedge of mass M and inclination θ. Wedge is accelerated with a=g tan θ as shown in figure. The acceleration of block with respect to wedge is (assume all surfaces to be smooth)


A
zero
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B
2g sinθ
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C
g sinθ(1tanθ)
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D
g sinθ(1+tanθ)
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Solution

The correct option is B 2g sinθ
Drawing FBD of block m from the frame of wedge,

let a0 is acceleration of block with respect of wedge,

ma0=ma cos θ+mg sin θ

a0=g tan θ cos θ+g sin θ

a0=2g sin θ

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