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Byju's Answer

Standard XII

Physics

Varying Mass System

A block of ma...

Question

A block of mass $M$ is situated on a smooth horizontal table. A thread tied to the block passes through a hole in the table and carries a mass $m$ at its other end. If the length of the thread above the table is $l$ and $M$ is revolving in a horizontal circle with angular speed $ω$ on the table, then the value of $m$ so that it remains suspended at a constant height $h$ is:

{M g h ω}^{2}

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{M g l ω}^{2}

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\frac{M {l ω}^{2}}{g}

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M {l ω}^{2}

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Solution

The correct option is D $\frac{M {l ω}^{2}}{g}$
The mass $m$ will remain in constant height when its weight balance the centripetal force on $M$ .
i.e, $m g = M w^{2} l \Rightarrow m = \frac{M w^{2} l}{g}$

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The correct option is D Mlω2gThe mass m will remain in constant height when its weight balance the centripetal force on M.i.e, mg=Mw2l⇒m=Mw2lg

The correct option is D $\frac{M {l ω}^{2}}{g}$
The mass $m$ will remain in constant height when its weight balance the centripetal force on $M$ .
i.e, $m g = M w^{2} l \Rightarrow m = \frac{M w^{2} l}{g}$