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Question

# A block of mass m kg is kept on a weighing machine in an elevator. If the elevator is retarding upward by a ms−2 the reading of weighing machine is (in kgf):

A
mg
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B
m(ga)
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C
m(1ag)
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D
m(g+a)
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Solution

## The correct option is D m(g+a)Motion in an elevator or lift :1) If the man inside the lift falls freely under gravity without any upward force then the apparent weight is zero. 2) If he falls with an acceleration a less than g then he experiences an upward force of m(g - a) and hence his apparent weight is m(g-a). 3) If he moves up with an acceleration a he experiences an upward force of m(g +a) and his apparent weight is equal to m(g + a). From the explanations above the answer is :m(g+a)

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