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Question

A block of mass m kg is sliding from rest on an inclined rough surface of inclination ) as shown in the figure under the action of three forces, weight, normal and frictional force only The magnitude of forces are 20N,40N and 50N not necessarily in the same order The value of g is 10 m/s2 Now match the physical quantity in List I with their magnitude in List II in SI unit and select the correct answer .

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Solution

Weight of block=mg
Normal acting on the block=μmg
Frictional force acting on block=μN=μmgcosθ
mg>mgcosθ>μmgcosθ
Since 50N>40N>20N,
mg=50N
mgcosθ=40N
μmgcosθ=20N
cosθ=45,
& μ=0.5

A) mg=50N
m=5kg

B) a=gsinθfm=6205=2m/s2

C) Net force acting on block during motion=ma=10N

D)μ=0.5
8μ=4

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