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Question

# A block of mass m moving at a velocity v collides head on with another block of mass 2m at rest. If the coefficient of restitution is 12, find the velocities of the blocks after the collision.

A

V2,V2

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B

V2,V2

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C

V2,0

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D

0,V2

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Solution

## The correct option is D 0,V2 Suppose after the collision the block of mass m moves at a velocity u1 and the block of mass 2m moves at a velocity u2. By conservation of momentum, mv = mu1+2mu2 ..........(i) the velocity of separation is u2−u1 and the velocity of approach is −v. so, u2−u1 = −12×(−v) ...........(ii) from (i) and (ii), u1 = 0 and u2 = v2

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