wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A block of mass m moving with velocity v0 on a smooth horizontal surface hits the spring of constant k as shown.The maxi um compression in spring is

A
2mk.v0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
mk.v0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
m2k.v0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2mk.v0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B mk.v0
For maximum compression,the kinetic energy of the blcok gets converted to the potential energy of the spring:
12mv20=12kx2
x2=mv20k
x=mk.v0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Energy in SHM
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon