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Question

A block of mass 'm' resting on a smooth horizontal floor is attached to a spring of force constant 'K' whose other end is attached to a rigid wall as shown in the figure above. A second block of mass 'm' is projected directly towards the first block with a velocity 'u'. After a collision, the two blocks stick together. The maximum compression in the spring is
392.bmp

A
mu2K
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B
2mu2K
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C
mu22K
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D
mu24K
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Solution

The correct option is D mu22K
Its an example of inelastic collision so, energy is not conserved all the time.
Momentum conservation is applicable.
mu=2mv
v=u2
Now after the collision, we can apply energy conservation.
Maximum compression when kinetic energy is zero.
12(2m)u24=12Kx2
x=mu22K

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