A block of mass m rests on a rough inclined plane. The coefficient of friction between the surface and the block if μ. At what angle of inclination θ of the plane to the horizontal will the block just start to slide down the plane?
A
θ=tan−1μ
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B
θ=cos−1μ
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C
θ=sin−1μ
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D
θ=sec−1μ
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Solution
The correct option is Aθ=tan−1μ The various forces acting on the block are as shown in the figure. From figure mgsinθ=f ............(i) mgcosθ=N .........(ii) Divide (i) by (ii), we get tanθ=fN=μNN or θ=tan−1(μ)