A block of mass m slides with velocity of $10 m / s$ on a rough horizontal surface. It comes to rest after converting a distance of $50$ meters. If $g$ is $10 m / s e c^{2}$ , then the coefficient of dynamic friction between the block and the surface is

0.1

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Solution

The correct option is A $0.1$
Given,

Initial velocity, $u = 10 m s^{- 1}$

Displacement, $s = 50 m$

Final velocity, $v = 0$

Acceleration of friction, $a = μ g = 10 μ m s^{- 2}$

Apply second kinematic equation of motion,

$v^{2} - u^{2} = 2 a s$

$0 - 10^{2} = 2 (- 10 μ) \times 50$

$μ = 0.1$

Hence, coefficient of friction is $0.1$

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A block of mass m slides with velocity of 10 m/s on a rough horizontal surface. It comes to rest after converting a distance of 50 meters. If g is 10 m/sec2, then the coefficient of dynamic friction between the block and the surface is

The correct option is A 0.1Given, Initial velocity, u=10ms−1 Displacement, s=50m Final velocity, v=0 Acceleration of friction, a=μg=10μms−2 Apply second kinematic equation of motion, v2−u2=2as 0−102=2(−10μ)×50 μ=0.1 Hence, coefficient of friction is 0.1

A block of mass m slides with velocity of $10 m / s$ on a rough horizontal surface. It comes to rest after converting a distance of $50$ meters. If $g$ is $10 m / s e c^{2}$ , then the coefficient of dynamic friction between the block and the surface is