wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A block of mass m suspended from a spring executes vertical SHM of time period T as shown in the figure. The amplitude of the SHM is A and the spring is never in compressed state during the oscillation. The magnitude of minimum force exerted by the spring on the block is


A
mg4π2T2mA
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
mg+4π2T2mA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
mgπ2T2mA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
mg+π2T2mA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A mg4π2T2mA

The spring is never compressed. Hence, spring exerts least force on the block when the block is at topmost position during SHM.
At equilibrium position, we know that kx0=mgx0=mgk
Fmin=k(x0A)=k[mgkA]
F=mgmω2A
[ω2=km]
Using ω=2πT, we get
Fmin=mg4π2T2mA
Thus, option (a) is the correct answer.

flag
Suggest Corrections
thumbs-up
5
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon