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Question

A block of mass of 10 kg is kept on rough inclined plane is kept inside a lift. At t = 0, the system is set in motion, the lift accelerates upwards with 10 m/s2. Find the work done by normal reaction on the block in one second with respect to lift. (m = 10 kg; θ=370; μ=0.8; a0=10m/s2)
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Solution

Normal force N=(ma+ma)cosθ
Frictional force fs
fs=μN
=μ(ma+mg)cosθ
Acceleration of block is a1 then we have,
(mg+ma)sinθfs=ma1
(mg+ma)sinθμ(ma+mg)cosθ =ma1
a1=(10×10+10×10)350.8(10×10+10×10)4510
=120.8×16=0.8
Here, a1 is positive means block do not move with respect to lift.
Hence work done by Normal reaction=0 w.r.t lift.

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