A block of mass 1 kg is placed on a rough incline as shown. The coefficient of friction between block and incline is 0.4. The acceleration of block is (g=10 ms−2,√3=1.7)
A
zero
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B
1.6 ms−2
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C
6.5 ms−2
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D
5 ms−2
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Solution
The correct option is B1.6 ms−2 Applied force on the block is its own weight along the incline F=mgsinθ =1×10×12=5N
Limiting friction f=μmgcosθ =0.4×1×10×√32 =2√3 =3.4 N
For F>f, body slips
Net force =mgsinθ−μmgcosθ =5−3.4=1.6
i.e ma=1.6N a=1.6 m/s2