A block of material has a density $ρ_{1}$ and floats three-fourth submerged in a liquid of unknown density. Show that the density $ρ_{2}$ of the unknown liquid is given by $ρ_{2} = \frac{4}{3} ρ_{1}$ .

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Solution

Weight=upthrust
$V_{ρ_{1}} g = (\frac{3}{4} V) ρ_{2} g$
$∴$ $ρ_{2} = \frac{4}{3} ρ_{1}$

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