A block of metal weighing $2 k g$ is resting on a frictionless plane. It is struck by a jet releasing water at the rate of $1 k g s^{- 1}$ and at a speed of $5$ $m s^{- 1}$ . Calculate the initial acceleration of the block.

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Solution

Change in momentum of water =mass $\times$ initial velocity=5 kg m/s
As given mass flow rate per unit second=1 kg /s
Now Force $= \frac{C h a n g e i n m o m e n t u m}{T i m e}$ =5N
And we know Force=mass $\times$ acceleration
Thus a $= \frac{F o r c e}{m a s s} = \frac{5}{2} = 2.5 m / s^{2}$

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A block of metal weighing 2 kg is resting on a frictionless plane. It is struck by a jet releasing water at the rate of 1 kg s−1 and at a speed of 5 ms−1. Calculate the initial acceleration of the block.

Change in momentum of water =mass×initial velocity=5 kg m/sAs given mass flow rate per unit second=1 kg /sNow Force=ChangeinmomentumTime=5NAnd we know Force=mass×accelerationThus a=Forcemass=52=2.5m/s2

A block of metal weighing $2 k g$ is resting on a frictionless plane. It is struck by a jet releasing water at the rate of $1 k g s^{- 1}$ and at a speed of $5$ $m s^{- 1}$ . Calculate the initial acceleration of the block.

Change in momentum of water =mass $\times$ initial velocity=5 kg m/s
As given mass flow rate per unit second=1 kg /s
Now Force $= \frac{C h a n g e i n m o m e n t u m}{T i m e}$ =5N
And we know Force=mass $\times$ acceleration
Thus a $= \frac{F o r c e}{m a s s} = \frac{5}{2} = 2.5 m / s^{2}$